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a^2-4a+1=-5
We move all terms to the left:
a^2-4a+1-(-5)=0
We add all the numbers together, and all the variables
a^2-4a+6=0
a = 1; b = -4; c = +6;
Δ = b2-4ac
Δ = -42-4·1·6
Δ = -8
Delta is less than zero, so there is no solution for the equation
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